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13x^2-8x+15/13=0
We multiply all the terms by the denominator
13x^2*13-8x*13+15=0
Wy multiply elements
169x^2-104x+15=0
a = 169; b = -104; c = +15;
Δ = b2-4ac
Δ = -1042-4·169·15
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-26}{2*169}=\frac{78}{338} =3/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+26}{2*169}=\frac{130}{338} =5/13 $
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